What is the f(x)=(3(x^2+1)^2(x^2-2x-1))/((x-1)^4) ?

The f(x)=(3(x^2+1)^2(x^2-2x-1))/((x-1)^4) is

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f(x)=(3(x^2+1)^2(x^2-2x-1))/((x-1)^4)

f (x) = \frac{3 ( x ^{2} + 1 ) ^{2} ( x ^{2} - 2 x - 1 )}{( x - 1 ) ^{4}}

Domain : x < 1 or x > 1

X Intercepts : (1 + 2, 0), (1 - 2, 0), Y Intercepts : (0, - 3)

Asymptotes : Vertical x = 1

Extreme Points : None

Interval Notation

Domain : (- \infty, 1) \cup (1, \infty)

Solution steps

Domain of

\frac{3 ( x ^{2} + 1 ) ^{2} ( x ^{2} - 2 x - 1 )}{( x - 1 ) ^{4}} : x < 1 or x > 1

Axis interception points of

\frac{3 ( x ^{2} + 1 ) ^{2} ( x ^{2} - 2 x - 1 )}{( x - 1 ) ^{4}} :

X Intercepts

: (1 + 2, 0), (1 - 2, 0),

Y Intercepts

: (0, - 3)

Asymptotes of

\frac{3 ( x ^{2} + 1 ) ^{2} ( x ^{2} - 2 x - 1 )}{( x - 1 ) ^{4}} :

Vertical

: x = 1

Extreme Points of

\frac{3 ( x ^{2} + 1 ) ^{2} ( x ^{2} - 2 x - 1 )}{( x - 1 ) ^{4}} :

None

(x + 3 x^{3} sin (y)) d x + x^{4} cos (y) d y

cos (x) (sec (x) + tan (x))

(2 - 3 x)^{2}

2 (ln (\frac{2}{3}) - 1)

A (- 3, 6) y B (5, - 8)

What is the f(x)=(3(x^2+1)^2(x^2-2x-1))/((x-1)^4) ?
The f(x)=(3(x^2+1)^2(x^2-2x-1))/((x-1)^4) is