What is 1/((s-i)^3)+1/((s+i)^3) ?

The solution to 1/((s-i)^3)+1/((s+i)^3) is (2s^3-6s)/(s^6+3s^4+3s^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 1/((s-i)^3)+1/((s+i)^3)

simplify

\frac{1}{( s - i ) ^{3}} + \frac{1}{( s + i ) ^{3}}

\frac{2 s ^{3} - 6 s}{s ^{6} + 3 s ^{4} + 3 s ^{2} + 1}

Solution steps

\frac{1}{( s - i ) ^{3}} + \frac{1}{( s + i ) ^{3}}

\frac{1}{( s - i ) ^{3}} = \frac{s ^{3} - 3 s + i ( 3 s ^{2} - 1 )}{s ^{6} + 3 s ^{4} + 3 s ^{2} + 1}

\frac{1}{( s + i ) ^{3}} = \frac{s ^{3} - 3 s + i ( - 3 s ^{2} + 1 )}{s ^{6} + 3 s ^{4} + 3 s ^{2} + 1}

= \frac{s ^{3} - 3 s + i ( 3 s ^{2} - 1 )}{s ^{6} + 3 s ^{4} + 3 s ^{2} + 1} + \frac{s ^{3} - 3 s + i ( - 3 s ^{2} + 1 )}{s ^{6} + 3 s ^{4} + 3 s ^{2} + 1}

Join

\frac{s ^{3} - 3 s + i ( 3 s ^{2} - 1 )}{s ^{6} + 3 s ^{4} + 3 s ^{2} + 1} + \frac{s ^{3} - 3 s + i ( - 3 s ^{2} + 1 )}{s ^{6} + 3 s ^{4} + 3 s ^{2} + 1} : \frac{2 s ^{3} - 6 s}{s ^{6} + 3 s ^{4} + 3 s ^{2} + 1}

= \frac{2 s ^{3} - 6 s}{s ^{6} + 3 s ^{4} + 3 s ^{2} + 1}

\frac{1}{( s + 5 ) ( s - 4 )}

(4 x^{3} + 5) \cdot (x^{4} + 5 x)^{\frac{1}{2}}

((X - 4) X - 1) \cdot (53 + 5 X - 1)

\frac{( 1 + 3 j ) ( 1 + 7 j )}{( 7 - 9 j ) ( 2 - j )}

(x - \frac{1}{2}) (x - 1)

What is 1/((s-i)^3)+1/((s+i)^3) ?
The solution to 1/((s-i)^3)+1/((s+i)^3) is (2s^3-6s)/(s^6+3s^4+3s^2+1)