What is expand Dx(1/3 sec^3(2x)-sec(2x)) ?

The solution to expand Dx(1/3 sec^3(2x)-sec(2x)) is Dx 1/3 sec^3(2x)-Dxsec(2x)

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expand Dx(1/3 sec^3(2x)-sec(2x))

expand

D x (\frac{1}{3} sec^{3} (2 x) - sec (2 x))

D x \frac{1}{3} sec^{3} (2 x) - D x sec (2 x)

Solution steps

D x (\frac{1}{3} sec^{3} (2 x) - sec (2 x))

Apply the distributive law:

a (b - c) = ab - a c

D x (\frac{1}{3} sec^{3} (2 x) - sec (2 x)) = D x \frac{1}{3} sec^{3} (2 x) - D x sec (2 x)

= D x \frac{1}{3} sec^{3} (2 x) - D x sec (2 x)

(u - 1)^{2} u

\frac{5 ( x + 3 )}{3 x}

(x + 3) \cdot (x^{2} - 4)

(x + 2) (x - 3) (x + \frac{1}{5})

(x + y - x - y)^{2}

What is expand Dx(1/3 sec^3(2x)-sec(2x)) ?
The solution to expand Dx(1/3 sec^3(2x)-sec(2x)) is Dx 1/3 sec^3(2x)-Dxsec(2x)