What is expand x((2+x}{-15}-\frac{x-4)/3 =4) ?

The solution to expand x((2+x}{-15}-\frac{x-4)/3 =4) is -(2x^2)/5+(6x)/5 =4

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expand x((2+x}{-15}-\frac{x-4)/3 =4)

expand

x (\frac{2 + x}{- 15} - \frac{x - 4}{3} = 4)

- \frac{2 x ^{2}}{5} + \frac{6 x}{5} = 4

Solution steps

x (\frac{2 + x}{- 15} - \frac{x - 4}{3} = 4)

= x (\frac{2 + x}{- 15} - 4 = \frac{x - 4}{3})

Apply the distributive law:

a (b - c) = ab - a c

a = x, b = \frac{2 + x}{- 15}, c = \frac{x - 4}{3} = 4

x \frac{2 + x}{- 15} - x \frac{x - 4}{3} = 4

Expand

x \frac{2 + x}{- 15} - x \frac{x - 4}{3} : - \frac{2 x ^{2}}{5} + \frac{6 x}{5}

- \frac{2 x ^{2}}{5} + \frac{6 x}{5} = 4

\frac{( x ^{2} - a ^{2} )}{( x + b ) ( x - c )}

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π (1717 + 55)

(n - 7) (n + 37)

What is expand x((2+x}{-15}-\frac{x-4)/3 =4) ?
The solution to expand x((2+x}{-15}-\frac{x-4)/3 =4) is -(2x^2)/5+(6x)/5 =4