What is expand 3x(3x-40+1=0) ?

The solution to expand 3x(3x-40+1=0) is 9x^2-117x=0

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expand 3x(3x-40+1=0)

expand

3 x (3 x - 40 + 1 = 0)

9 x^{2} - 117 x = 0

Solution steps

3 x (3 x - 40 + 1 = 0)

= 3 x (3 x - 40 + 1 \cdot 0 =)

Distribute parentheses

3 x \cdot 3 x + 3 x (- 40) + 3 x \cdot 1 = 0

Apply minus-plus rules

+ (- a) = - a

3 \cdot 3 xx - 3 \cdot 40 x + 3 \cdot 1 \cdot x = 0

Expand

3 \cdot 3 xx - 3 \cdot 40 x + 3 \cdot 1 \cdot x : 9 x^{2} - 117 x

9 x^{2} - 117 x = 0

\frac{7 x + 10}{( x + 1 ) ( x ^{2} - 4 )}

((3 x^{3} + 5 y)^{2})^{2}

lo g_{10} \frac{( x + 4 ) ^{5}}{x ^{3}}

\frac{p ( x )}{( x ^{2} + 1 ) ( x - 3 )}

(k + 1)!

What is expand 3x(3x-40+1=0) ?
The solution to expand 3x(3x-40+1=0) is 9x^2-117x=0