What are the solutions to the equation x^2+2x+9=0 ?

The solutions to the equation x^2+2x+9=0 are x=-1+2sqrt(2)i,x=-1-2sqrt(2)i

Find the zeros of x^2+2x+9=0

The zeros of x^2+2x+9=0 are x=-1+2sqrt(2)i,x=-1-2sqrt(2)i

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x^{2} + 2 x + 9 = 0

x = - 1 + 22 i, x = - 1 - 22 i

Solution steps

x^{2} + 2 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 9 : 42 i

x_{1, 2} = \frac{- 2 \pm 4 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 2 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 2 i}{2 \cdot 1}

x = \frac{- 2 + 4 2 i}{2 \cdot 1} : - 1 + 22 i

x = \frac{- 2 - 4 2 i}{2 \cdot 1} : - 1 - 22 i

The solutions to the quadratic equation are:

x = - 1 + 22 i, x = - 1 - 22 i

(- \frac{27}{8})^{\frac{2}{3}}

\frac{1}{1 + e ^{- 1}}

\frac{2}{3} - \frac{2}{4}

\frac{3}{2} \cdot 2

0 = 3 x^{2} + 3 x + 7

What are the solutions to the equation x^2+2x+9=0 ?
The solutions to the equation x^2+2x+9=0 are x=-1+2sqrt(2)i,x=-1-2sqrt(2)i
Find the zeros of x^2+2x+9=0
The zeros of x^2+2x+9=0 are x=-1+2sqrt(2)i,x=-1-2sqrt(2)i