What is 2((-u-3)/(49)+1/7) ?

The solution to 2((-u-3)/(49)+1/7) is (2(-u+4))/(49)

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simplify 2((-u-3)/(49)+1/7)

simplify

2 (\frac{- u - 3}{49} + \frac{1}{7})

\frac{2 ( - u + 4 )}{49}

Solution steps

2 (\frac{- u - 3}{49} + \frac{1}{7})

Join

\frac{- u - 3}{49} + \frac{1}{7} : \frac{- u + 4}{49}

= 2 \cdot \frac{- u + 4}{49}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 ( - u + 4 )}{49}

16 (s + s^{'})^{12}

\frac{( - 1 + 2 sin ( x ) )}{( sin ( x ) - 2 ) ^{2}}

F (4, - 3)

\frac{( 2 x + 1 ) ^{3}}{3}

\frac{5 ( 2 3 + 3 )}{3}

What is 2((-u-3)/(49)+1/7) ?
The solution to 2((-u-3)/(49)+1/7) is (2(-u+4))/(49)