What is expand-(16x)/((x^2-4)^2) ?

The solution to expand-(16x)/((x^2-4)^2) is -(16x)/(x^4-8x^2+16)

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expand-(16x)/((x^2-4)^2)

expand

- \frac{16 x}{( x ^{2} - 4 ) ^{2}}

- \frac{16 x}{x ^{4} - 8 x ^{2} + 16}

Solution steps

- \frac{16 x}{( x ^{2} - 4 ) ^{2}}

(x^{2} - 4)^{2} = x^{4} - 8 x^{2} + 16

= - \frac{16 x}{x ^{4} - 8 x ^{2} + 16}

(\frac{x ^{9} y ^{\frac{1}{3}}}{z} + 2 pt) (\frac{x ^{9} y ^{\frac{1}{3}}}{z} - 6 pt)

\frac{( 4 y ^{8} - 1 ) ^{2}}{16 y ^{8}}

(1 - 3 x - 2) (1 - 3 x + 2)

(2 x^{3} + \frac{1}{x})^{10}

\frac{( - 2 x - 10 ) ( 3 - x )}{( x ^{2} + 5 ) ( x - 2 ) ^{2}}

What is expand-(16x)/((x^2-4)^2) ?
The solution to expand-(16x)/((x^2-4)^2) is -(16x)/(x^4-8x^2+16)