What are the solutions to the equation r^2+64r=0 ?

The solutions to the equation r^2+64r=0 are r=0,r=-64

Find the zeros of r^2+64r=0

The zeros of r^2+64r=0 are r=0,r=-64

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} + 64 r = 0

r = 0, r = - 64

Solution steps

r^{2} + 64 r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

6 4^{2} - 4 \cdot 1 \cdot 0 = 64

r_{1, 2} = \frac{- 64 \pm 64}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 64 + 64}{2 \cdot 1}, r_{2} = \frac{- 64 - 64}{2 \cdot 1}

r = \frac{- 64 + 64}{2 \cdot 1} : 0

r = \frac{- 64 - 64}{2 \cdot 1} : - 64

The solutions to the quadratic equation are:

r = 0, r = - 64

n^{2} = - 72

∣ 5 x - 13 ∣ = - 7

\frac{29520 - 200}{200} \leq 0.35

x^{3} - 2 x^{2} - 11 x + 12

3 x^{2} - 8 x - 11

What are the solutions to the equation r^2+64r=0 ?
The solutions to the equation r^2+64r=0 are r=0,r=-64
Find the zeros of r^2+64r=0
The zeros of r^2+64r=0 are r=0,r=-64