What is expand (1-y^{1/3})^2 ?

The solution to expand (1-y^{1/3})^2 is 1-2y^{1/3}+y^{2/3}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (1-y^{1/3})^2

expand

(1 - y^{\frac{1}{3}})^{2}

1 - 2 y^{\frac{1}{3}} + y^{\frac{2}{3}}

Solution steps

(1 - y^{\frac{1}{3}})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(1 - y^{\frac{1}{3}})^{2} = 1^{2} - 2 \cdot 1 \cdot y^{\frac{1}{3}} + (y^{\frac{1}{3}})^{2}

= 1^{2} - 2 \cdot 1 \cdot y^{\frac{1}{3}} + (y^{\frac{1}{3}})^{2}

1^{2} = 1

2 \cdot 1 \cdot y^{\frac{1}{3}} = 2 y^{\frac{1}{3}}

(y^{\frac{1}{3}})^{2} = y^{\frac{2}{3}}

= 1 - 2 y^{\frac{1}{3}} + y^{\frac{2}{3}}

(p - 1 - p)^{2}

(a + b 3) (c + d 3)

(2 e^{y} + 3 x sin (y)) d x + (x e^{y} + x^{2} cos (x)) d y

h (1 - 4 + 2 h)

(- (2 t^{2} - 4 t + 2)^{2}, t^{2}) \cdot (1, 4 t - 4)

What is expand (1-y^{1/3})^2 ?
The solution to expand (1-y^{1/3})^2 is 1-2y^{1/3}+y^{2/3}