What is expand (8/x-1/(x^3))^2 ?

The solution to expand (8/x-1/(x^3))^2 is (64x^4-16x^2+1)/(x^6)

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expand (8/x-1/(x^3))^2

expand

(\frac{8}{x} - \frac{1}{x ^{3}})^{2}

\frac{64 x ^{4} - 16 x ^{2} + 1}{x ^{6}}

Solution steps

(\frac{8}{x} - \frac{1}{x ^{3}})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(\frac{8}{x} - \frac{1}{x ^{3}})^{2} = (\frac{8}{x})^{2} - 2 \cdot \frac{8}{x} \cdot \frac{1}{x ^{3}} + (\frac{1}{x ^{3}})^{2}

= (\frac{8}{x})^{2} - 2 \cdot \frac{8}{x} \cdot \frac{1}{x ^{3}} + (\frac{1}{x ^{3}})^{2}

Simplify

(\frac{8}{x})^{2} - 2 \cdot \frac{8}{x} \cdot \frac{1}{x ^{3}} + (\frac{1}{x ^{3}})^{2} : \frac{64 x ^{4} - 16 x ^{2} + 1}{x ^{6}}

= \frac{64 x ^{4} - 16 x ^{2} + 1}{x ^{6}}

\frac{2}{9} \cdot (3 + \frac{9}{5}) - 1.5 \cdot \frac{4}{5}

(m + n) (m - n)

5 (x + 3 - 5 (x^{2} - 1) = x^{2} + 7 (3 - x) - 1)

m (9.81 - \frac{2 s}{t ^{2}})

What is expand (8/x-1/(x^3))^2 ?
The solution to expand (8/x-1/(x^3))^2 is (64x^4-16x^2+1)/(x^6)