What is expand ((x^2+1)(x^4-x^2+1))/(x^3) ?

The solution to expand ((x^2+1)(x^4-x^2+1))/(x^3) is x^3+1/(x^3)

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expand ((x^2+1)(x^4-x^2+1))/(x^3)

expand

\frac{( x ^{2} + 1 ) ( x ^{4} - x ^{2} + 1 )}{x ^{3}}

x^{3} + \frac{1}{x ^{3}}

Solution steps

\frac{( x ^{2} + 1 ) ( x ^{4} - x ^{2} + 1 )}{x ^{3}}

Expand

(x^{2} + 1) (x^{4} - x^{2} + 1) : x^{6} + 1

= \frac{x ^{6} + 1}{x ^{3}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{6} + 1}{x ^{3}} = \frac{x ^{6}}{x ^{3}} + \frac{1}{x ^{3}}

= \frac{x ^{6}}{x ^{3}} + \frac{1}{x ^{3}}

Cancel

\frac{x ^{6}}{x ^{3}} : x^{3}

= x^{3} + \frac{1}{x ^{3}}

(\frac{a}{2} - b)^{5}

P (9, - 2, 5) y Q (3, 0, - 1)

(x + y - 1) d x + (2 x + 2 y + 3) d y

8 (5 - 2)

\frac{( 1 - x ^{2} )}{( x ^{2} - 4 ) ^{2}}

What is expand ((x^2+1)(x^4-x^2+1))/(x^3) ?
The solution to expand ((x^2+1)(x^4-x^2+1))/(x^3) is x^3+1/(x^3)