What is expand 5/((s-2)(s-3)(s-6)) ?

The solution to expand 5/((s-2)(s-3)(s-6)) is 5/(s^3-11s^2+36s-36)

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expand 5/((s-2)(s-3)(s-6))

expand

\frac{5}{( s - 2 ) ( s - 3 ) ( s - 6 )}

\frac{5}{s ^{3} - 11 s ^{2} + 36 s - 36}

Solution steps

\frac{5}{( s - 2 ) ( s - 3 ) ( s - 6 )}

Expand

(s - 2) (s - 3) (s - 6) : s^{3} - 11 s^{2} + 36 s - 36

= \frac{5}{s ^{3} - 11 s ^{2} + 36 s - 36}

\frac{x}{( x ^{2} + 9 ) ^{2}}

\frac{6}{( x + 1 ) ^{4}}

(D + \frac{2}{25}) (D - \frac{1}{25})

\frac{1}{4} (\frac{3}{8} + 2 \cdot (0.3 (\frac{1}{4} (\frac{2}{16}))))

(x + \frac{3}{2}) (x - \frac{3}{2})

What is expand 5/((s-2)(s-3)(s-6)) ?
The solution to expand 5/((s-2)(s-3)(s-6)) is 5/(s^3-11s^2+36s-36)