What is expand (A+B=2,)(-2A+C=3) ?

The solution to expand (A+B=2,)(-2A+C=3) is -2A^2+AC=3

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expand (A+B=2,)(-2A+C=3)

expand

(A + B = 2,) (- 2 A + C = 3)

- 2 A^{2} + A C = 3

Solution steps

(A + B = 2,) (- 2 A + C = 3)

= (A + 2 =, B) (- 2 A + 3 = C)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = A, b = B = 2,, c = - 2 A, d = C = 3

A (- 2 A) + A C = 3 + B = 2, (- 2 A) + B = 2, C = 3

Apply minus-plus rules

+ (- a) = - a

- 2 AA + A C = 3 - B = 2, 2 A + B = 2, C = 3

Expand

- 2 AA + A C : - 2 A^{2} + A C

- 2 A^{2} + A C = 3

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(x y - x) d x - (x^{2} + 1) d y

(- x sin^{2} (y) - x cos^{2} (y))^{2}

What is expand (A+B=2,)(-2A+C=3) ?
The solution to expand (A+B=2,)(-2A+C=3) is -2A^2+AC=3