What is expand (1-i,2+3i)*(2+i,3-2i) ?

The solution to expand (1-i,2+3i)*(2+i,3-2i) is 1*2+1i,3-1*2i-i,2*2-i,2i,3+i,2*2i+3*2i+3ii,3-3*2ii

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expand (1-i,2+3i)*(2+i,3-2i)

expand

(1 - i, 2 + 3 i) \cdot (2 + i, 3 - 2 i)

1 \cdot 2 + 1 i, 3 - 1 \cdot 2 i - i, 2 \cdot 2 - i, 2 i, 3 + i, 2 \cdot 2 i + 3 \cdot 2 i + 3 ii, 3 - 3 \cdot 2 ii

Solution steps

(1 - i, 2 + 3 i) (2 + i, 3 - 2 i)

= (1 - 2 i, + 3 i) (2 + 3 i, - 2 i)

Distribute parentheses

= 1 \cdot 2 + 1 i, 3 + 1 \cdot (- 2 i) + (- i, 2) \cdot 2 + (- i, 2) i, 3 + (- i, 2) (- 2 i) + 3 i 2 + 3 ii, 3 + 3 i (- 2 i)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= 1 \cdot 2 + 1 i, 3 - 1 \cdot 2 i - i, 2 \cdot 2 - i, 2 i, 3 + i, 2 \cdot 2 i + 3 \cdot 2 i + 3 ii, 3 - 3 \cdot 2 ii

\frac{x + 4}{x ( x + 6 )}

x (x^{4} e^{11 x} + 3)

3 (5 - 2)

(r cos (θ) + r^{2} - 1) (2 r^{2} cos (θ))

4 (3 s^{2} (2 s^{2} + 25 s + (\frac{5}{s})) + 22 s^{2}) + 10

What is expand (1-i,2+3i)*(2+i,3-2i) ?
The solution to expand (1-i,2+3i)*(2+i,3-2i) is 1*2+1i,3-1*2i-i,2*2-i,2i,3+i,2*2i+3*2i+3ii,3-3*2ii