What is expand 1/((pi^2h^2-p^2L^2)^2) ?

The solution to expand 1/((pi^2h^2-p^2L^2)^2) is 1/(pi^4h^4-2pi^2h^2L^2p^2+L^4p^4)

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expand 1/((pi^2h^2-p^2L^2)^2)

expand

\frac{1}{( π ^{2} h ^{2} - p ^{2} L ^{2} ) ^{2}}

\frac{1}{π ^{4} h ^{4} - 2 π ^{2} h ^{2} L ^{2} p ^{2} + L ^{4} p ^{4}}

Solution steps

\frac{1}{( π ^{2} h ^{2} - p ^{2} L ^{2} ) ^{2}}

(π^{2} h^{2} - p^{2} L^{2})^{2} = π^{4} h^{4} - 2 π^{2} h^{2} L^{2} p^{2} + L^{4} p^{4}

= \frac{1}{π ^{4} h ^{4} - 2 π ^{2} h ^{2} L ^{2} p ^{2} + L ^{4} p ^{4}}

(x + 3)^{2} d x

(3 + 2)^{4}

y (x + y + 1) d x

lo g_{10} (2) (1 + x^{2})

\frac{x ^{2} - 4 x + 5}{x ( x + 1 ) \cdot ( x + 2 )}

What is expand 1/((pi^2h^2-p^2L^2)^2) ?
The solution to expand 1/((pi^2h^2-p^2L^2)^2) is 1/(pi^4h^4-2pi^2h^2L^2p^2+L^4p^4)