What is expand (2x^2-2x+2)/((2x-1)^2) ?

The solution to expand (2x^2-2x+2)/((2x-1)^2) is (2x^2-2x+2)/(4x^2-4x+1)

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expand (2x^2-2x+2)/((2x-1)^2)

expand

\frac{2 x ^{2} - 2 x + 2}{( 2 x - 1 ) ^{2}}

\frac{2 x ^{2} - 2 x + 2}{4 x ^{2} - 4 x + 1}

Solution steps

\frac{2 x ^{2} - 2 x + 2}{( 2 x - 1 ) ^{2}}

(2 x - 1)^{2} = 4 x^{2} - 4 x + 1

= \frac{2 x ^{2} - 2 x + 2}{4 x ^{2} - 4 x + 1}

(2 - 1) (25 + 3)

\frac{2 x ^{3} + 3 x ^{2} + x - 1}{( x + 1 ) ( x ^{2} + 2 x + 2 ) ^{2}}

(1 - u_{2 π} (t)) sin (t)

(2 x - 3 y^{2}) (y^{2} - 3 z) (x^{\frac{11}{3}} - \frac{1}{y ^{\frac{1}{2}}})

π (4 - x^{2})^{2}

What is expand (2x^2-2x+2)/((2x-1)^2) ?
The solution to expand (2x^2-2x+2)/((2x-1)^2) is (2x^2-2x+2)/(4x^2-4x+1)