What is expand \H(t-a)f(t-a) ?

The solution to expand \H(t-a)f(t-a) is tf\H(t-a)-af\H(t-a)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand \H(t-a)f(t-a)

expand

H (t - a) f (t - a)

t f H (t - a) - a f H (t - a)

Solution steps

H (t - a) f (t - a)

= f H (t - a) (t - a)

Apply the distributive law:

a (b - c) = ab - a c

a = H (t - a) f, b = t, c = a

= H (t - a) f t - H (t - a) f a

= t f H (t - a) - a f H (t - a)

(3 - x - 3)^{2}

P (- 1, - 1) C (3, 5)

\frac{sin ( x + h ) - sin ( x )}{h}

\frac{\partial}{\partial x} ((z) (e^{2 z} - x yz))

\frac{3 ( x - 1 )}{4}

What is expand \H(t-a)f(t-a) ?
The solution to expand \H(t-a)f(t-a) is tf\H(t-a)-af\H(t-a)