What is expand (sqrt(t)+2t)^4+(sqrt(t)-2t)^4 ?

The solution to expand (sqrt(t)+2t)^4+(sqrt(t)-2t)^4 is 32t^4+48t^3+2t^2

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expand (sqrt(t)+2t)^4+(sqrt(t)-2t)^4

expand

(t + 2 t)^{4} + (t - 2 t)^{4}

32 t^{4} + 48 t^{3} + 2 t^{2}

Solution steps

(t + 2 t)^{4} + (t - 2 t)^{4}

Expand

(t + 2 t)^{4} : t^{2} + 8 t (t)^{3} + 24 t^{3} + 32 t^{3} t + 16 t^{4}

= t^{2} + 8 t (t)^{3} + 24 t^{3} + 32 t^{3} t + 16 t^{4} + (t - 2 t)^{4}

Expand

(t - 2 t)^{4} : t^{2} - 8 t (t)^{3} + 24 t^{3} - 32 t^{3} t + 16 t^{4}

= t^{2} + 8 t (t)^{3} + 24 t^{3} + 32 t^{3} t + 16 t^{4} + t^{2} - 8 t (t)^{3} + 24 t^{3} - 32 t^{3} t + 16 t^{4}

Simplify

t^{2} + 8 t (t)^{3} + 24 t^{3} + 32 t^{3} t + 16 t^{4} + t^{2} - 8 t (t)^{3} + 24 t^{3} - 32 t^{3} t + 16 t^{4} : 32 t^{4} + 48 t^{3} + 2 t^{2}

= 32 t^{4} + 48 t^{3} + 2 t^{2}

tan (θ) (sec (θ) - 1)

\frac{( 16 x ^{4} )}{3 \cdot ( 9 - x ^{2} )}

\frac{60 s + 1200}{s ( s + 10 ) ^{2}}

- 6 x^{\frac{5}{3}} (- 2 x^{\frac{1}{2}} + 3 x^{\frac{1}{3}})

(2 a + b)^{2}

What is expand (sqrt(t)+2t)^4+(sqrt(t)-2t)^4 ?
The solution to expand (sqrt(t)+2t)^4+(sqrt(t)-2t)^4 is 32t^4+48t^3+2t^2