What are the solutions to the equation 2x^2+12x-14=0 ?

The solutions to the equation 2x^2+12x-14=0 are x=1,x=-7

Find the zeros of 2x^2+12x-14=0

The zeros of 2x^2+12x-14=0 are x=1,x=-7

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2 x^{2} + 12 x - 14 = 0

x = 1, x = - 7

Solution steps

2 x^{2} + 12 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 ( - 14 )}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 (- 14) = 16

x_{1, 2} = \frac{- 12 \pm 16}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 12 + 16}{2 \cdot 2}, x_{2} = \frac{- 12 - 16}{2 \cdot 2}

x = \frac{- 12 + 16}{2 \cdot 2} : 1

x = \frac{- 12 - 16}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

x = 1, x = - 7

p (c - d) + c - d

\frac{5 !}{2 !}

\frac{0}{- 11}

(1 + 2)^{2}

15 x^{2} + 16 x + 4 = 0

What are the solutions to the equation 2x^2+12x-14=0 ?
The solutions to the equation 2x^2+12x-14=0 are x=1,x=-7
Find the zeros of 2x^2+12x-14=0
The zeros of 2x^2+12x-14=0 are x=1,x=-7