What is (x-4)(x-2+3i)(x+2+3i) ?

The solution to (x-4)(x-2+3i)(x+2+3i) is (x-4)(x^2-13)+(x-4)*6xi

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simplify (x-4)(x-2+3i)(x+2+3i)

simplify

(x - 4) (x - 2 + 3 i) (x + 2 + 3 i)

(x - 4) (x^{2} - 13) + (x - 4) \cdot 6 x i

Solution steps

(x - 4) (x - 2 + 3 i) (x + 2 + 3 i)

Rewrite

x - 2 + 3 i

in standard complex form:

(x - 2) + 3 i

Rewrite

x + 2 + 3 i

in standard complex form:

(x + 2) + 3 i

= (x - 4) ((x - 2) + 3 i) ((x + 2) + 3 i)

Apply complex arithmetic rule:

(a + bi) (c + d i) = (a c - b d) + (a d + b c) i

= (x - 4) (((x - 2) (x + 2) - 3 \cdot 3) + ((x - 2) \cdot 3 + 3 (x + 2)) i)

Simplify

((x - 2) (x + 2) - 3 \cdot 3) + ((x - 2) \cdot 3 + 3 (x + 2)) i : (x^{2} - 13) + 6 x i

= (x - 4) ((x^{2} - 13) + 6 x i)

Distribute parentheses

= (x - 4) (x^{2} - 13) + (x - 4) \cdot 6 x i

(x^{2} + y^{2} + z^{2}) x^{2} + y^{2} + z^{2}

x (200 - \frac{x}{30})

\frac{( x + 1 ) ( x - 1 )}{x}

\frac{2}{( s - 1 ) ( s - 2 ) e ^{s}}

(4 x^{2} - 4 x) \cdot (1 + Δ x)

What is (x-4)(x-2+3i)(x+2+3i) ?
The solution to (x-4)(x-2+3i)(x+2+3i) is (x-4)(x^2-13)+(x-4)*6xi