What is expand (e^'-2xy)y'(x) ?

The solution to expand (e^'-2xy)y'(x) is e^'y'(x)-2xy'(x)y

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expand (e^'-2xy)y'(x)

expand

(e^{^{'}} - 2 x y) y^{'} (x)

e^{'} y' (x) - 2 x y' (x) y

Solution steps

(e^{^{'}} - 2 x y) y^{'} (x)

Apply the distributive law:

a (b - c) = ab - a c

a = y^{'} (x), b = e^{^{'}}, c = 2 x y

= y^{^{'}} (x) e^{^{^{'}}} - y^{^{'}} (x) 2 x y

= e^{^{^{'}}} y^{^{'}} (x) - 2 x y^{^{'}} (x) y

\frac{d}{d t} ((x) (5 t - 5 ln (t)))

\frac{\frac{d}{d x} ( - 3 3 x - 4 )}{( 3 x ^{3} - 3 ) ^{2}}

cos (x^{2} + 2 x y + y^{2}) (2 y + 2 x) (x + y)

x^{\frac{2}{3}} (\frac{5}{2} - x)

7 (9 + 2)

What is expand (e^'-2xy)y'(x) ?
The solution to expand (e^'-2xy)y'(x) is e^'y'(x)-2xy'(x)y