What is expand (4x^{1/2}+5)(4x^{1/2}-5) ?

The solution to expand (4x^{1/2}+5)(4x^{1/2}-5) is 16x-25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (4x^{1/2}+5)(4x^{1/2}-5)

expand

(4 x^{\frac{1}{2}} + 5) (4 x^{\frac{1}{2}} - 5)

16 x - 25

Solution steps

(4 x^{\frac{1}{2}} + 5) (4 x^{\frac{1}{2}} - 5)

Apply Difference of Two Squares

(4 x^{\frac{1}{2}} + 5) (4 x^{\frac{1}{2}} - 5) : 16 x - 25

= 16 x - 25

(2 - x^{2}) 2 - x^{2}

\frac{x + 1}{( x + 2 ) ( x - 3 )}

\frac{( x + 7 ) ^{7}}{8}

cot (4 x) (sin (4 x) + 2 sin (4 x) cos (3 x))

\frac{( x ^{2} + 3 x + 2 )}{( x + 2 )}

What is expand (4x^{1/2}+5)(4x^{1/2}-5) ?
The solution to expand (4x^{1/2}+5)(4x^{1/2}-5) is 16x-25