What is expand 2log_{10}(3)(1-x)+3 ?

The solution to expand 2log_{10}(3)(1-x)+3 is 2log_{10}(3)-2log_{10}(3)x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 2log_{10}(3)(1-x)+3

expand

2 lo g_{10} (3) (1 - x) + 3

2 lo g_{10} (3) - 2 lo g_{10} (3) x + 3

Solution steps

2 lo g_{10} (3) (1 - x) + 3

Apply the distributive law:

a (b - c) = ab - a c

2 lo g_{10} (3) (1 - x) = 2 lo g_{10} (3) \cdot 1 - 2 lo g_{10} (3) x

= 2 lo g_{10} (3) \cdot 1 - 2 lo g_{10} (3) x + 3

Multiply the numbers:

2 \cdot 1 = 2

= 2 lo g_{10} (3) - 2 lo g_{10} (3) x + 3

\frac{2 x}{( x + 1 ) ( x - 1 )}

(x - 2 x + 1)^{2}

A (- 2, - 3) y B (5, 1)

\frac{3 x ^{2} + x + 2}{x ^{2} ( x ^{2} + 4 )}

\frac{( x + 1 ) ( 2 x - 1 )}{x + 2}

What is expand 2log_{10}(3)(1-x)+3 ?
The solution to expand 2log_{10}(3)(1-x)+3 is 2log_{10}(3)-2log_{10}(3)x+3