What is expand (x^3+1)/((x-1)^2) ?

The solution to expand (x^3+1)/((x-1)^2) is (x^3+1)/(x^2-2x+1)

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expand (x^3+1)/((x-1)^2)

expand

\frac{x ^{3} + 1}{( x - 1 ) ^{2}}

\frac{x ^{3} + 1}{x ^{2} - 2 x + 1}

Solution steps

\frac{x ^{3} + 1}{( x - 1 ) ^{2}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{x ^{3} + 1}{x ^{2} - 2 x + 1}

a (e^{b x^{2}} + 2 b e^{b x^{2}} x^{2})

2 (3 s + 1) (s + \frac{1}{14})

det (- x (x + 2) (x + 3))

(1 + ln (x) + \frac{y}{x}) d x

- \frac{e ^{- \frac{πjn}{2}} ( 2 πjn + 1 )}{π ^{2} j ^{2} n ^{2}}

What is expand (x^3+1)/((x-1)^2) ?
The solution to expand (x^3+1)/((x-1)^2) is (x^3+1)/(x^2-2x+1)