What is expand ((4x-1)(4x+1))/2 ?

The solution to expand ((4x-1)(4x+1))/2 is 8x^2-1/2

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expand ((4x-1)(4x+1))/2

expand

\frac{( 4 x - 1 ) ( 4 x + 1 )}{2}

8 x^{2} - \frac{1}{2}

Solution steps

\frac{( 4 x - 1 ) ( 4 x + 1 )}{2}

Expand

(4 x - 1) (4 x + 1) : 16 x^{2} - 1

= \frac{16 x ^{2} - 1}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 x ^{2} - 1}{2} = \frac{16 x ^{2}}{2} - \frac{1}{2}

= \frac{16 x ^{2}}{2} - \frac{1}{2}

Divide the numbers:

\frac{16}{2} = 8

= 8 x^{2} - \frac{1}{2}

- 3 (x - \frac{π}{6})

A (- 3, - 2, 1)

7 (ln (x) + 1)

o (lo g_{2} (n) + 5)

What is expand ((4x-1)(4x+1))/2 ?
The solution to expand ((4x-1)(4x+1))/2 is 8x^2-1/2