What is expand 1/4 (2x-7)(2x-1) ?

The solution to expand 1/4 (2x-7)(2x-1) is x^2-4x+7/4

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expand 1/4 (2x-7)(2x-1)

expand

\frac{1}{4} (2 x - 7) (2 x - 1)

x^{2} - 4 x + \frac{7}{4}

Solution steps

\frac{1}{4} (2 x - 7) (2 x - 1)

Expand

\frac{1}{4} (2 x - 7) (2 x - 1) : \frac{1}{4} (4 x^{2} - 16 x + 7)

= \frac{1}{4} (4 x^{2} - 16 x + 7)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

\frac{1}{4} (4 x^{2} - 16 x + 7) = \frac{1}{4} \cdot 4 x^{2} + \frac{1}{4} (- 16 x) + \frac{1}{4} \cdot 7

= \frac{1}{4} \cdot 4 x^{2} + \frac{1}{4} (- 16 x) + \frac{1}{4} \cdot 7

Simplify

\frac{1}{4} \cdot 4 x^{2} + \frac{1}{4} (- 16 x) + \frac{1}{4} \cdot 7 : x^{2} - 4 x + \frac{7}{4}

= x^{2} - 4 x + \frac{7}{4}

- 4 cos^{2} (t) - 2 sin (t) (2 sin (t) + 16)

\frac{( 7 x + 3 m ) ^{2}}{36}

(3 x - 2) e^{x}

(x + i x^{2})^{2}

\frac{3 ( 2 x - 3 y )}{( 2 x + 3 y )}

What is expand 1/4 (2x-7)(2x-1) ?
The solution to expand 1/4 (2x-7)(2x-1) is x^2-4x+7/4