What is expand (2e^y-1/8 e^{-y})^2 ?

The solution to expand (2e^y-1/8 e^{-y})^2 is 4e^{2y}-1/2+1/64 e^{-2y}

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expand (2e^y-1/8 e^{-y})^2

expand

(2 e^{y} - \frac{1}{8} e^{- y})^{2}

4 e^{2 y} - \frac{1}{2} + \frac{1}{64} e^{- 2 y}

Solution steps

(2 e^{y} - \frac{1}{8} e^{- y})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = 2 e^{y}, b = \frac{1}{8} e^{- y}

= (2 e^{y})^{2} - 2 \cdot 2 e^{y} \frac{1}{8} e^{- y} + (\frac{1}{8} e^{- y})^{2}

Simplify

(2 e^{y})^{2} - 2 \cdot 2 e^{y} \frac{1}{8} e^{- y} + (\frac{1}{8} e^{- y})^{2} : 4 e^{2 y} - \frac{1}{2} + \frac{1}{64} e^{- 2 y}

= 4 e^{2 y} - \frac{1}{2} + \frac{1}{64} e^{- 2 y}

\frac{3 ( 14 + 106 )}{4}

x sin (y) d y + (x^{3} - 2 x^{2} cos (y) + cos (y)) d x

(1 + x) cos (x)

(x^{2} - y^{2} + 1 - 1) (x^{2} - y^{2} + 1 + 1)

(x + c)^{2} + y^{2}

What is expand (2e^y-1/8 e^{-y})^2 ?
The solution to expand (2e^y-1/8 e^{-y})^2 is 4e^{2y}-1/2+1/64 e^{-2y}