What is expand ((2-x)^3)/6 ?

The solution to expand ((2-x)^3)/6 is -(x^3)/6+x^2-2x+4/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((2-x)^3)/6

expand

\frac{( 2 - x ) ^{3}}{6}

- \frac{x ^{3}}{6} + x^{2} - 2 x + \frac{4}{3}

Solution steps

\frac{( 2 - x ) ^{3}}{6}

(2 - x)^{3} = 8 - 12 x + 6 x^{2} - x^{3}

= \frac{8 - 12 x + 6 x ^{2} - x ^{3}}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{8 - 12 x + 6 x ^{2} - x ^{3}}{6} = \frac{8}{6} - \frac{12 x}{6} + \frac{6 x ^{2}}{6} - \frac{x ^{3}}{6}

= \frac{8}{6} - \frac{12 x}{6} + \frac{6 x ^{2}}{6} - \frac{x ^{3}}{6}

Cancel

\frac{8}{6} : \frac{4}{3}

= \frac{4}{3} - \frac{12 x}{6} + \frac{6 x ^{2}}{6} - \frac{x ^{3}}{6}

Divide the numbers:

\frac{12}{6} = 2

= \frac{4}{3} - 2 x + \frac{6 x ^{2}}{6} - \frac{x ^{3}}{6}

Divide the numbers:

\frac{6}{6} = 1

= \frac{4}{3} - 2 x + x^{2} - \frac{x ^{3}}{6}

Rewrite in standard form

= - \frac{x ^{3}}{6} + x^{2} - 2 x + \frac{4}{3}

a (- 5, 2) b (4, - 3)

\frac{1 + 3 x + x ^{2}}{( x - 19 ) ( x - 2 ) ( x + 6 )}

(x - 3 y) (x + 3 y)

α (2, 1, - 2)

\frac{k ( s + 1.5 )}{s ( s + 1 ) ( s + 10 ) + 1.5 k}

What is expand ((2-x)^3)/6 ?
The solution to expand ((2-x)^3)/6 is -(x^3)/6+x^2-2x+4/3