What is expand (x(x^2-3x+4))/((x-1)^3) ?

The solution to expand (x(x^2-3x+4))/((x-1)^3) is (x^3-3x^2+4x)/(x^3-3x^2+3x-1)

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expand (x(x^2-3x+4))/((x-1)^3)

expand

\frac{x ( x ^{2} - 3 x + 4 )}{( x - 1 ) ^{3}}

\frac{x ^{3} - 3 x ^{2} + 4 x}{x ^{3} - 3 x ^{2} + 3 x - 1}

Solution steps

\frac{x ( x ^{2} - 3 x + 4 )}{( x - 1 ) ^{3}}

(x - 1)^{3} = x^{3} - 3 x^{2} + 3 x - 1

= \frac{x ( x ^{2} - 3 x + 4 )}{x ^{3} - 3 x ^{2} + 3 x - 1}

Expand

x (x^{2} - 3 x + 4) : x^{3} - 3 x^{2} + 4 x

= \frac{x ^{3} - 3 x ^{2} + 4 x}{x ^{3} - 3 x ^{2} + 3 x - 1}

(t + 1)^{\frac{2}{3}} (2 t^{2} - 1)^{3}

6 (6 sec^{2} (3 x - 2) tan^{2} (3 x - 2) + 3 sec^{4} (3 x - 2))

(3 x - 10 y) (\frac{y}{2} + x^{2})

(2 x - 4) (2 x + 4)

What is expand (x(x^2-3x+4))/((x-1)^3) ?
The solution to expand (x(x^2-3x+4))/((x-1)^3) is (x^3-3x^2+4x)/(x^3-3x^2+3x-1)