What is expand (x+1)/((x-3)(x+4)) ?

The solution to expand (x+1)/((x-3)(x+4)) is (x+1)/(x^2+x-12)

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expand (x+1)/((x-3)(x+4))

expand

\frac{x + 1}{( x - 3 ) ( x + 4 )}

\frac{x + 1}{x ^{2} + x - 12}

Solution steps

\frac{x + 1}{( x - 3 ) ( x + 4 )}

Expand

(x - 3) (x + 4) : x^{2} + x - 12

= \frac{x + 1}{x ^{2} + x - 12}

(2 x^{\frac{2}{3}} - x) (x^{3} + 3 x)

(2 + x) (3 - x)

ln (x + 4)

\frac{9 ( 375 x - 3 )}{25}

(1 - sin (x^{2}))^{2}

What is expand (x+1)/((x-3)(x+4)) ?
The solution to expand (x+1)/((x-3)(x+4)) is (x+1)/(x^2+x-12)