What is expand (2s+1)/((s-3)(s^2+2)) ?

The solution to expand (2s+1)/((s-3)(s^2+2)) is (2s+1)/(s^3+2s-3s^2-6)

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expand (2s+1)/((s-3)(s^2+2))

expand

\frac{2 s + 1}{( s - 3 ) ( s ^{2} + 2 )}

\frac{2 s + 1}{s ^{3} + 2 s - 3 s ^{2} - 6}

Solution steps

\frac{2 s + 1}{( s - 3 ) ( s ^{2} + 2 )}

Expand

(s - 3) (s^{2} + 2) : s^{3} + 2 s - 3 s^{2} - 6

= \frac{2 s + 1}{s ^{3} + 2 s - 3 s ^{2} - 6}

(cos (a) - sin (a)) (sec (a) + csc (a))

(s^{\frac{1}{2}} - t^{\frac{1}{2}})^{2}

2 x (e^{x} - 1) - 15

(a + b) (c + d) (e + f)

d o m (x^{2} - 4)

What is expand (2s+1)/((s-3)(s^2+2)) ?
The solution to expand (2s+1)/((s-3)(s^2+2)) is (2s+1)/(s^3+2s-3s^2-6)