What is expand P((0.1)/(2,1))Q(2,1,-3) ?

The solution to expand P((0.1)/(2,1))Q(2,1,-3) is 2((0.1)/(2*1,))PQ,1,-3((0.1)/(2*1,))PQ

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expand P((0.1)/(2,1))Q(2,1,-3)

expand

P (\frac{0.1}{2 , 1}) Q (2, 1, - 3)

2 (\frac{0.1}{2 \cdot 1 ,}) PQ, 1, - 3 (\frac{0.1}{2 \cdot 1 ,}) PQ

Solution steps

P (\frac{0.1}{2 , 1}) Q (2, 1, - 3)

= (\frac{0.1}{2 \cdot 1 ,}) (2 \cdot 1,, - 3) PQ

Apply the distributive law:

a (b - c) = ab - a c

a = P (\frac{0.1}{2 , 1}) Q, b = 2, 1,, c = 3

= P (\frac{0.1}{2 , 1}) Q \cdot 2, 1, - P (\frac{0.1}{2 , 1}) Q \cdot 3

= 2 (\frac{0.1}{2 \cdot 1 ,}) PQ, 1, - 3 (\frac{0.1}{2 \cdot 1 ,}) PQ

\frac{- 3}{4} sec^{3} (\frac{π}{2})

A (2, 7) y B (- 6, - 9)

\frac{( 2 y ^{4} + 2 y ^{2} + 1 ) ( 2 y ^{4} - 2 y ^{2} + 1 ) d y}{4 y ^{4}}

(x - i)^{4}

e^{x} (e^{x} + 1)

What is expand P((0.1)/(2,1))Q(2,1,-3) ?
The solution to expand P((0.1)/(2,1))Q(2,1,-3) is 2((0.1)/(2*1,))PQ,1,-3((0.1)/(2*1,))PQ