What is expand y(5x+3y-3z=0,)(2x+y-3z=1) ?

The solution to expand y(5x+3y-3z=0,)(2x+y-3z=1) is 10yx^2+5y^2x-15yxz=1

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expand y(5x+3y-3z=0,)(2x+y-3z=1)

expand

y (5 x + 3 y - 3 z = 0,) (2 x + y - 3 z = 1)

10 y x^{2} + 5 y^{2} x - 15 y x z = 1

Solution steps

y (5 x + 3 y - 3 z = 0,) (2 x + y - 3 z = 1)

= y (5 x + 3 y - 3 \cdot 0 =, z) (2 x + y - 3 \cdot 1 = z)

Expand

(5 x + 3 y - 3 z = 0,) (2 x + y - 3 z = 1) : 10 x^{2} + 5 y x - 15 x z = 1

= y (10 x^{2} + 5 y x - 15 x z = 1)

Expand

y (10 x^{2} + 5 y x - 15 x z = 1) : 10 y x^{2} + 5 y^{2} x - 15 y x z = 1

10 y x^{2} + 5 y^{2} x - 15 y x z = 1

\frac{x - 29}{( x - 4 ) ( x + 1 )}

\frac{1}{( x + 3 ) ( x + 1 )}

(- b + b^{2} - 4 a c)^{2}

\frac{x}{( x ^{2} + k ) ( x ^{2} + b x + c )}

2 + \frac{2 ( 5 x ^{2} - 14 x + 9 )}{8}

What is expand y(5x+3y-3z=0,)(2x+y-3z=1) ?
The solution to expand y(5x+3y-3z=0,)(2x+y-3z=1) is 10yx^2+5y^2x-15yxz=1