What is expand e^{-4(x+h)}-(e^{-4x}) ?

The solution to expand e^{-4(x+h)}-(e^{-4x}) is e^{-4x-4h}-e^{-4x}

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expand e^{-4(x+h)}-(e^{-4x})

expand

e^{- 4 (x + h)} - (e^{- 4 x})

e^{- 4 x - 4 h} - e^{- 4 x}

Solution steps

e^{- 4 (x + h)} - (e^{- 4 x})

Remove parentheses:

(a) = a

= e^{- 4 (x + h)} - e^{- 4 x}

Expand

- 4 (x + h) : - 4 x - 4 h

= e^{- 4 x - 4 h} - e^{- 4 x}

\frac{x + 6}{x ( x + 3 )}

(x + \frac{1}{4}) (x - \frac{3}{4})

H (t - 2) (t + 1)

\frac{( 2 s ^{2} - 1 ) ^{2}}{s ^{6}}

What is expand e^{-4(x+h)}-(e^{-4x}) ?
The solution to expand e^{-4(x+h)}-(e^{-4x}) is e^{-4x-4h}-e^{-4x}