What is expand (2x^2-3)/((x-1)^2) ?

The solution to expand (2x^2-3)/((x-1)^2) is (2x^2-3)/(x^2-2x+1)

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expand (2x^2-3)/((x-1)^2)

expand

\frac{2 x ^{2} - 3}{( x - 1 ) ^{2}}

\frac{2 x ^{2} - 3}{x ^{2} - 2 x + 1}

Solution steps

\frac{2 x ^{2} - 3}{( x - 1 ) ^{2}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{2 x ^{2} - 3}{x ^{2} - 2 x + 1}

\frac{25}{( t + 1 ) ^{2}}

\frac{( x ^{(2)} )}{( ( 1 - x ) ( 1 + x ^{(2)} ) ^{(2)} )}

4 (63 + 10 \cdot 1 0^{\frac{1}{2}})

\frac{\partial}{\partial s} ((x) (s + t))

\frac{x + 2}{x ( x ^{2} - 9 )}

What is expand (2x^2-3)/((x-1)^2) ?
The solution to expand (2x^2-3)/((x-1)^2) is (2x^2-3)/(x^2-2x+1)