What is expand ((3x-5)^3)/9 ?

The solution to expand ((3x-5)^3)/9 is 3x^3-15x^2+25x-125/9

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expand ((3x-5)^3)/9

expand

\frac{( 3 x - 5 ) ^{3}}{9}

3 x^{3} - 15 x^{2} + 25 x - \frac{125}{9}

Solution steps

\frac{( 3 x - 5 ) ^{3}}{9}

(3 x - 5)^{3} = 27 x^{3} - 135 x^{2} + 225 x - 125

= \frac{27 x ^{3} - 135 x ^{2} + 225 x - 125}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{27 x ^{3} - 135 x ^{2} + 225 x - 125}{9} = \frac{27 x ^{3}}{9} - \frac{135 x ^{2}}{9} + \frac{225 x}{9} - \frac{125}{9}

= \frac{27 x ^{3}}{9} - \frac{135 x ^{2}}{9} + \frac{225 x}{9} - \frac{125}{9}

Divide the numbers:

\frac{27}{9} = 3

= 3 x^{3} - \frac{135 x ^{2}}{9} + \frac{225 x}{9} - \frac{125}{9}

Divide the numbers:

\frac{135}{9} = 15

= 3 x^{3} - 15 x^{2} + \frac{225 x}{9} - \frac{125}{9}

Divide the numbers:

\frac{225}{9} = 25

= 3 x^{3} - 15 x^{2} + 25 x - \frac{125}{9}

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What is expand ((3x-5)^3)/9 ?
The solution to expand ((3x-5)^3)/9 is 3x^3-15x^2+25x-125/9