What is expand ((12-x)^2x)/(24) ?

The solution to expand ((12-x)^2x)/(24) is (x^3)/(24)-x^2+6x

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expand ((12-x)^2x)/(24)

expand

\frac{( 12 - x ) ^{2} x}{24}

\frac{x ^{3}}{24} - x^{2} + 6 x

Solution steps

\frac{( 12 - x ) ^{2} x}{24}

(12 - x)^{2} = 144 - 24 x + x^{2}

= \frac{x ( x ^{2} - 24 x + 144 )}{24}

Expand

(144 - 24 x + x^{2}) x : 144 x - 24 x^{2} + x^{3}

= \frac{144 x - 24 x ^{2} + x ^{3}}{24}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{144 x - 24 x ^{2} + x ^{3}}{24} = \frac{144 x}{24} - \frac{24 x ^{2}}{24} + \frac{x ^{3}}{24}

= \frac{144 x}{24} - \frac{24 x ^{2}}{24} + \frac{x ^{3}}{24}

Divide the numbers:

\frac{144}{24} = 6

= 6 x - \frac{24 x ^{2}}{24} + \frac{x ^{3}}{24}

Divide the numbers:

\frac{24}{24} = 1

= 6 x - x^{2} + \frac{x ^{3}}{24}

Rewrite in standard form

= \frac{x ^{3}}{24} - x^{2} + 6 x

\frac{\frac{d}{d x} ( e ^{x^{2} + x} + x )}{( x + 2 ) ^{2}}

(6 t + 5) (7)

y (2 x^{2} - y^{2} = 3)

(- 5 + e^{i t})^{3}

\frac{k}{( s + 1 ) ^{3}}

What is expand ((12-x)^2x)/(24) ?
The solution to expand ((12-x)^2x)/(24) is (x^3)/(24)-x^2+6x