What is (0.06325)/(j(6.4821j+0.004j^{31.62)+1)} ?

The solution to (0.06325)/(j(6.4821j+0.004j^{31.62)+1)} is (253)/(4000j(6.4821j+0.004j^{31.62)+1)}

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simplify (0.06325)/(j(6.4821j+0.004j^{31.62)+1)}

simplify

\frac{0.06325}{j ( 6.4821 j + 0.004 j ^{31.62} + 1 )}

\frac{253}{4000 j ( 6.4821 j + 0.004 j ^{31.62} + 1 )}

Solution steps

\frac{0.06325}{j ( 6.4821 j + 0.004 j ^{31.62} + 1 )}

Simplify

\frac{0.06325}{j ( 6.4821 j + 0.004 j ^{31.62} + 1 )} : \frac{6325}{100000 j ( 6.4821 j + 0.004 j ^{31.62} + 1 )}

= \frac{6325}{100000 j ( 6.4821 j + 0.004 j ^{31.62} + 1 )}

Factor the number:

6325 = 25 \cdot 253

= \frac{25 \cdot 253}{100000 j ( 6.4821 j + 0.004 j ^{31.62} + 1 )}

Factor the number:

100000 = 25 \cdot 4000

= \frac{25 \cdot 253}{25 \cdot 4000 j ( 6.4821 j + 0.004 j ^{31.62} + 1 )}

Cancel the common factor:

25

= \frac{253}{4000 j ( 6.4821 j + 0.004 j ^{31.62} + 1 )}

(\frac{6}{7} - x)^{2}

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\frac{9 \cdot 1 6 ^{n} + 1 6 ^{n + 1}}{( 4 ^{n + 2} + 4 ^{n + 1} ) ^{2}}

cot (x) (cos (2 x) - 1)

(i - 12) (i + 9)

What is (0.06325)/(j(6.4821j+0.004j^{31.62)+1)} ?
The solution to (0.06325)/(j(6.4821j+0.004j^{31.62)+1)} is (253)/(4000j(6.4821j+0.004j^{31.62)+1)}