What is expand ((x+3)(x-7))/((x+4)(x-5)) ?

The solution to expand ((x+3)(x-7))/((x+4)(x-5)) is (x^2-4x-21)/(x^2-x-20)

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expand ((x+3)(x-7))/((x+4)(x-5))

expand

\frac{( x + 3 ) ( x - 7 )}{( x + 4 ) ( x - 5 )}

\frac{x ^{2} - 4 x - 21}{x ^{2} - x - 20}

Solution steps

\frac{( x + 3 ) ( x - 7 )}{( x + 4 ) ( x - 5 )}

Expand

(x + 4) (x - 5) : x^{2} - x - 20

= \frac{( x + 3 ) ( x - 7 )}{x ^{2} - x - 20}

Expand

(x + 3) (x - 7) : x^{2} - 4 x - 21

= \frac{x ^{2} - 4 x - 21}{x ^{2} - x - 20}

\frac{x + 2}{( x - 4 ) ( x - 2 )}

\frac{4 b ( a b ^{2} - a ^{5} )}{( a ^{4} + b ^{2} ) ^{2}}

\frac{8640 e ^{- 0.96 t}}{( 1 + 3 e ^{- 0.96 t} ) ^{2}}

c (1 - \frac{u ^{2}}{x ^{2}})

\frac{1}{\frac{1}{\frac{1}{r _{1}} + \frac{1}{r _{2}}} + \frac{1}{r _{π}}}

What is expand ((x+3)(x-7))/((x+4)(x-5)) ?
The solution to expand ((x+3)(x-7))/((x+4)(x-5)) is (x^2-4x-21)/(x^2-x-20)