What is expand (x^2-8x+12)/((x-4)^2) ?

The solution to expand (x^2-8x+12)/((x-4)^2) is (x^2-8x+12)/(x^2-8x+16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x^2-8x+12)/((x-4)^2)

expand

\frac{x ^{2} - 8 x + 12}{( x - 4 ) ^{2}}

\frac{x ^{2} - 8 x + 12}{x ^{2} - 8 x + 16}

Solution steps

\frac{x ^{2} - 8 x + 12}{( x - 4 ) ^{2}}

(x - 4)^{2} = x^{2} - 8 x + 16

= \frac{x ^{2} - 8 x + 12}{x ^{2} - 8 x + 16}

x^{\frac{1}{3}} (x^{2} - 42)

\frac{\frac{d}{d x} ( ( y ) ( y ^{2} + 2 x y ) )}{x ^{2}}

(t + e^{t - 5}) U (t - 5)

3 (5 + 7)

2 \frac{d y}{d x} - (10 - 4 sin (t)) y

What is expand (x^2-8x+12)/((x-4)^2) ?
The solution to expand (x^2-8x+12)/((x-4)^2) is (x^2-8x+12)/(x^2-8x+16)