What is expand (x+1-i)(x+1+i) ?

The solution to expand (x+1-i)(x+1+i) is x^2+2x+2

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expand (x+1-i)(x+1+i)

expand

(x + 1 - i) (x + 1 + i)

x^{2} + 2 x + 2

Solution steps

(x + 1 - i) (x + 1 + i)

Distribute parentheses

= xx + x \cdot 1 + x i + 1 \cdot x + 1 \cdot 1 + 1 i - i x - i 1 - ii

Simplify

xx + x \cdot 1 + x i + 1 \cdot x + 1 \cdot 1 + 1 i - i x - i 1 - ii : x^{2} + 2 x + 2

= x^{2} + 2 x + 2

\frac{2 ( ( - 1 ) ^{n} - 1 )}{π n ^{2}}

(2 y - \frac{1}{x})^{10}

\frac{( s + 3 )}{s ( s + 1 ) ( s + 2 )}

cos (x) (sec (x) + 3 sin (x))

- \frac{2 ( - 3 x ^{2} + 4 )}{( x ^{2} + 4 ) ^{3}}

What is expand (x+1-i)(x+1+i) ?
The solution to expand (x+1-i)(x+1+i) is x^2+2x+2