What is expand ((x-3)^2(2x-3))/((x-4)(x+2)) ?

The solution to expand ((x-3)^2(2x-3))/((x-4)(x+2)) is (2x^3-15x^2+36x-27)/(x^2-2x-8)

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expand ((x-3)^2(2x-3))/((x-4)(x+2))

expand

\frac{( x - 3 ) ^{2} ( 2 x - 3 )}{( x - 4 ) ( x + 2 )}

\frac{2 x ^{3} - 15 x ^{2} + 36 x - 27}{x ^{2} - 2 x - 8}

Solution steps

\frac{( x - 3 ) ^{2} ( 2 x - 3 )}{( x - 4 ) ( x + 2 )}

(x - 3)^{2} = x^{2} - 6 x + 9

= \frac{( x ^{2} - 6 x + 9 ) ( 2 x - 3 )}{( x - 4 ) ( x + 2 )}

Expand

(x - 4) (x + 2) : x^{2} - 2 x - 8

= \frac{( x ^{2} - 6 x + 9 ) ( 2 x - 3 )}{x ^{2} - 2 x - 8}

Expand

(x^{2} - 6 x + 9) (2 x - 3) : 2 x^{3} - 15 x^{2} + 36 x - 27

= \frac{2 x ^{3} - 15 x ^{2} + 36 x - 27}{x ^{2} - 2 x - 8}

t^{\frac{5}{2}} (t^{2} - 10 t + 16)

\frac{s + 4}{s ( s + 0.5 ) ( s + 1 ) ( s ^{2} + 0.4 s + 4 )}

(4 + 4 cos (θ))^{2}

\frac{13 x - 18 y}{6 ( a - b )}

(2 x + 3) d x

What is expand ((x-3)^2(2x-3))/((x-4)(x+2)) ?
The solution to expand ((x-3)^2(2x-3))/((x-4)(x+2)) is (2x^3-15x^2+36x-27)/(x^2-2x-8)