What is 8(-(cos^4(x))/4+(cos^6(x))/6) ?

The solution to 8(-(cos^4(x))/4+(cos^6(x))/6) is (2(-3cos^4(x)+2cos^6(x)))/3

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simplify 8(-(cos^4(x))/4+(cos^6(x))/6)

simplify

8 (- \frac{cos ^{4} ( x )}{4} + \frac{cos ^{6} ( x )}{6})

\frac{2 ( - 3 cos ^{4} ( x ) + 2 cos ^{6} ( x ) )}{3}

Solution steps

8 (- \frac{cos ^{4} ( x )}{4} + \frac{cos ^{6} ( x )}{6})

Join

- \frac{cos ^{4} ( x )}{4} + \frac{cos ^{6} ( x )}{6} : \frac{- cos ^{4} ( x ) \cdot 3 + cos ^{6} ( x ) \cdot 2}{12}

= 8 \cdot \frac{- cos ^{4} ( x ) \cdot 3 + cos ^{6} ( x ) \cdot 2}{12}

= 8 \cdot \frac{- 3 cos ^{4} ( x ) + 2 cos ^{6} ( x )}{12}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{8 ( - 3 cos ^{4} ( x ) + 2 cos ^{6} ( x ) )}{12}

Cancel

\frac{8 ( - 3 cos ^{4} ( x ) + 2 cos ^{6} ( x ) )}{12} : \frac{2 ( - 3 cos ^{4} ( x ) + 2 cos ^{6} ( x ) )}{3}

= \frac{2 ( - 3 cos ^{4} ( x ) + 2 cos ^{6} ( x ) )}{3}

\frac{( 4 + x ) \cdot ( x - 1 )}{2}

\frac{( x + 1 ) ( x - 3 ) ( x - 5 )}{9}

A (- 5, 1) B (1, - 3)

(x - \frac{b}{2 a})^{2} - b (x - \frac{b}{2 a}) + c

\frac{6 ^{7}}{6 ^{4}}

What is 8(-(cos^4(x))/4+(cos^6(x))/6) ?
The solution to 8(-(cos^4(x))/4+(cos^6(x))/6) is (2(-3cos^4(x)+2cos^6(x)))/3