What is expand (1+t)^2-2cos(2t)+2sin(3t)-4e^{-3t} ?

The solution to expand (1+t)^2-2cos(2t)+2sin(3t)-4e^{-3t} is 1+2t+t^2-2cos(2t)+2sin(3t)-4e^{-3t}

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expand (1+t)^2-2cos(2t)+2sin(3t)-4e^{-3t}

expand

(1 + t)^{2} - 2 cos (2 t) + 2 sin (3 t) - 4 e^{- 3 t}

1 + 2 t + t^{2} - 2 cos (2 t) + 2 sin (3 t) - 4 e^{- 3 t}

Solution steps

(1 + t)^{2} - 2 cos (2 t) + 2 sin (3 t) - 4 e^{- 3 t}

(1 + t)^{2} : 1 + 2 t + t^{2}

= 1 + 2 t + t^{2} - 2 cos (2 t) + 2 sin (3 t) - 4 e^{- 3 t}

(e^{3 x} - e^{- 3 x})^{2}

\frac{\partial}{\partial x} ((z) (x^{2} + x y + y^{2}))

\frac{( 6 x - 5 ) ( x - 6 )}{x - 5}

\frac{( 2 + x ) ( 3 + 2 x ) ^{2}}{( 1.8 - 2 x ) ^{2} ( 1 - 2 x ) ^{2}}

x (4 - x + 2)

What is expand (1+t)^2-2cos(2t)+2sin(3t)-4e^{-3t} ?
The solution to expand (1+t)^2-2cos(2t)+2sin(3t)-4e^{-3t} is 1+2t+t^2-2cos(2t)+2sin(3t)-4e^{-3t}