What is (x-1/2)(x+3/2) ?

The solution to (x-1/2)(x+3/2) is ((2x-1)(2x+3))/4

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simplify (x-1/2)(x+3/2)

simplify

(x - \frac{1}{2}) (x + \frac{3}{2})

\frac{( 2 x - 1 ) ( 2 x + 3 )}{4}

Solution steps

(x - \frac{1}{2}) (x + \frac{3}{2})

Simplify

x - \frac{1}{2} : \frac{2 x - 1}{2}

= \frac{2 x - 1}{2} (x + \frac{3}{2})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 x - 1 ) ( x + \frac{3}{2} )}{2}

Simplify

(2 x - 1) (x + \frac{3}{2}) : \frac{( 2 x - 1 ) ( x \cdot 2 + 3 )}{2}

= \frac{\frac{( 2 x - 1 ) ( x \cdot 2 + 3 )}{2}}{2}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 2 x - 1 ) ( x \cdot 2 + 3 )}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{( 2 x - 1 ) ( x \cdot 2 + 3 )}{4}

= \frac{( 2 x - 1 ) ( 2 x + 3 )}{4}

(x - 2) (x + 2) [x - \frac{2}{x ^{2}} - 4 + \frac{1}{x} + 2 = \frac{1}{x} - 2]

\frac{1 + ln ( x )}{x ^{2} ( 1 - ln ( x ) ) ^{3}}

\frac{( x - 3 ) ( x + 6 )}{x + 7}

y^{'} (x) + \frac{( 1 - x ) y}{x}

(y^{- 1})^{4}