What is (\partial)/(\partial x)((y)(x-y)) ?

The answer to (\partial)/(\partial x)((y)(x-y)) is y

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(\partial)/(\partial x)((y)(x-y))

\frac{\partial}{\partial x} ((y) (x - y))

y

Solution steps

\frac{\partial}{\partial x} ((y) (x - y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (x - y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= y (\frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (y))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= y (1 - 0)

Simplify

= y

\frac{( e ^{- s} )}{s ( s ^{2} + 1 )}

(- 1 + 2 i)^{4}

\frac{( 3 - x ) ( x ^{2} + 2 )}{( x - 5 ) ( x + 3 )}

(40, - 4) y (40, 8)

lo g_{10} (x^{5} y^{- 12})

What is (\partial)/(\partial x)((y)(x-y)) ?
The answer to (\partial)/(\partial x)((y)(x-y)) is y