What is expand-sin(x)(1+sin(x)) ?

The solution to expand-sin(x)(1+sin(x)) is -sin(x)-sin^2(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-sin(x)(1+sin(x))

expand

- sin (x) (1 + sin (x))

- sin (x) - sin^{2} (x)

Solution steps

- sin (x) (1 + sin (x))

Apply the distributive law:

a (b + c) = ab + a c

- sin (x) (1 + sin (x)) = - sin (x) \cdot 1 - sin (x) sin (x)

= - sin (x) \cdot 1 - sin (x) sin (x)

Simplify

- sin (x) \cdot 1 - sin (x) sin (x) : - sin (x) - sin^{2} (x)

= - sin (x) - sin^{2} (x)

(1 + x - 3)^{2}

\frac{1}{x ( n - x )}

π r (g + r)

(x - 3 - 4)^{2}

\frac{s ^{2} ( s ^{3} + 2 s + 1 )}{s ^{5} + 3 s ^{4} + 2 s + 12}

What is expand-sin(x)(1+sin(x)) ?
The solution to expand-sin(x)(1+sin(x)) is -sin(x)-sin^2(x)