What is expand 1/2 ((2+ln(x))-(ln(x^2-4))) ?

The solution to expand 1/2 ((2+ln(x))-(ln(x^2-4))) is 1+1/2 ln(x)-1/2 ln(x^2-4)

Popular >

expand 1/2 ((2+ln(x))-(ln(x^2-4)))

expand

\frac{1}{2} ((2 + ln (x)) - (ln (x^{2} - 4)))

1 + \frac{1}{2} ln (x) - \frac{1}{2} ln (x^{2} - 4)

Solution steps

\frac{1}{2} ((2 + ln (x)) - (ln (x^{2} - 4)))

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{1}{2}, b = (2 + ln (x)), c = (ln (x^{2} - 4))

= \frac{1}{2} (2 + ln (x)) - \frac{1}{2} (ln (x^{2} - 4))

Simplify

\frac{1}{2} (2 + ln (x)) - \frac{1}{2} (ln (x^{2} - 4)) : 1 + \frac{1}{2} ln (x) - \frac{1}{2} ln (x^{2} - 4)

= 1 + \frac{1}{2} ln (x) - \frac{1}{2} ln (x^{2} - 4)

\frac{y ( 1 - y )}{1 - y}

x^{\frac{2}{3}} (x + 5)

(cos (x) - cot (x)) (cos (x) + cot (x))

(x^{\frac{1}{3}} - c^{\frac{1}{3}}) (x^{\frac{1}{3}} + c^{\frac{1}{3}})

\frac{1 - cos ( x ^{2} + y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

What is expand 1/2 ((2+ln(x))-(ln(x^2-4))) ?
The solution to expand 1/2 ((2+ln(x))-(ln(x^2-4))) is 1+1/2 ln(x)-1/2 ln(x^2-4)