What is expand 1/((s^2+1)(s^2+4s+8)) ?

The solution to expand 1/((s^2+1)(s^2+4s+8)) is 1/(s^4+4s^3+9s^2+4s+8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/((s^2+1)(s^2+4s+8))

expand

\frac{1}{( s ^{2} + 1 ) ( s ^{2} + 4 s + 8 )}

\frac{1}{s ^{4} + 4 s ^{3} + 9 s ^{2} + 4 s + 8}

Solution steps

\frac{1}{( s ^{2} + 1 ) ( s ^{2} + 4 s + 8 )}

Expand

(s^{2} + 1) (s^{2} + 4 s + 8) : s^{4} + 4 s^{3} + 9 s^{2} + 4 s + 8

= \frac{1}{s ^{4} + 4 s ^{3} + 9 s ^{2} + 4 s + 8}

6 (\frac{x ^{3}}{3} + 2 x^{2} + 4 x) + C

(sin (\frac{a}{2}) - cos (\frac{a}{2}))^{2}

\frac{5 ( x ^{2} + 4 )}{( x ^{2} - 49 ) ^{9}}

(t - i t^{2})^{2}

5 (15 + 22 e^{\frac{4 l n ( \frac{15}{22} )}{3}})

What is expand 1/((s^2+1)(s^2+4s+8)) ?
The solution to expand 1/((s^2+1)(s^2+4s+8)) is 1/(s^4+4s^3+9s^2+4s+8)